Validating Credit Card Numbers in Python - HackerRank solution

-

Solution for hackerRank problem Validating Credit Card Numbers in Python


Problem :

You and Fredrick are good friends. Yesterday, Fredrick received  N credit cards from ABCD Bank. He wants to verify whether his credit card numbers are valid or not. You happen to be great at regex so he is asking for your help!

A valid credit card from ABCD Bank has the following characteristics:

► It must start with a  4, 5 or 6.
► It must contain exactly  16 digits.
► It must only consist of digits (0-9).
► It may have digits in groups of 4, separated by one hyphen "-".
► It must NOT use any other separator like ' ' , '_', etc.
► It must NOT have  4 or more consecutive repeated digits.

Examples:

Valid Credit Card Numbers

4253625879615786
4424424424442444
5122-2368-7954-3214

InValid Credit Card Numbers

42536258796157867       #17 digits in card number → Invalid 
4424444424442444        #Consecutive digits are repeating 4 or more times → Invalid
5122-2368-7954 - 3214   #Separators other than '-' are used → Invalid
44244x4424442444        #Contains non digit characters → Invalid
0525362587961578        #Doesn't start with 4, 5 or 6 → Invalid

Input Format

The first line of input contains an integer N.
The next N lines contain credit card numbers.

Constraints

0 < N < 100

Output Format

Print 'Valid' if the credit card number is valid. Otherwise, print 'Invalid'. Do not print the quotes.

Sample Input

6
4123456789123456
5123-4567-8912-3456
61234-567-8912-3456
4123356789123456
5133-3367-8912-3456
5123 - 3567 - 8912 - 3456

Sample Output

Valid
Valid
Invalid
Valid
Invalid
Invalid

Explanation

4123456789123456 : Valid
5123-4567-8912-3456 : Valid
61234-567-8912-3456 : Invalid, because the card number is not divided into equal groups of .4
4123356789123456 : Valid
5133-3367-8912-3456 : Invalid, consecutive digits 3333 is repeating  4 times.
5123-4567-8912-3456 : Invalid, because space '  ' and - are used as separators.

Code :

n = int(input())
for i in range(n):
    
    card_no = str(input())
    if(card_no[0] not in ['4','5','6']):
        print("Invalid")
        continue
    flag = 0
    if(len(card_no)==16):
        q=0
        for d in range(len(card_no)-4):
            if(card_no[d]==card_no[d+1]==card_no[d+2]==card_no[d+3]):
                q=1 
                break
            else :
                continue
        if(q==1):
            flag = 1
            print("Invalid")
        
        for digit in card_no:
            if(digit.isdigit()):
                continue
            else :
                flag = 1
                print("Invalid")
                break
        if(flag == 0):
            print("Valid")
    elif(len(card_no)==19):
        flag = 0
        card = card_no.split("-")
        only_num = card[0]+card[1]+card[2]+card[3]
        r=0
        for j in range(len(only_num)-4):
            if(only_num[j]==only_num[j+1]==only_num[j+2]==only_num[j+3]):
                r = 1
                flag = 1
                print("Invalid") 
                break
            else :
                continue
        for each in card:
            if(len(each)!=4):
                flag = 1
                print("Invalid")
                break
            else :
                for p in range(len(each)):
                    if(each[p].isdigit()):
                        continue
                    else :
                        flag = 1
                        print("Invalid")
                        break
        if(flag == 0):
            print("Valid")
    else :
        print("Invalid")
    


Comments

Post a Comment

Popular posts from this blog

Finding the percentage in python - HackerRank solution

-
Solution for hackerRank problem Finding the percentage in python Problem : The provided code stub will read in a dictionary containing key/value pairs of name:[marks] for a list of students. Print the average of the marks array for the student name provided, showing 2 places after the decimal. Example The  query_name  is 'beta'. beta's average score is  . Input Format The first line contains the integer  , the number of students' records. The next lines contain the names and marks obtained by a student, each value separated by a space. The final line contains  query_name , the name of a student to query. Constraints 2<=n<=10 0<=marks[i]<=100 length of marks arrays = 3 Output Format Print one line: The average of the marks obtained by the particular student correct to 2 decimal places. Sample Input 0 3 Krishna 67 68 69 Arjun 70 98 63 Malika 52 56 60 Malika Sample Output 0 56.00 Explanation 0 Explanation 0 Marks for Malika are   whose average is  Sample Input
Read more

HackerRank challenges with solutions (Rearrangement, Formula, Word sorting, Numbers, Sentence)

-
Image
  1.  Rearrangement Given a list A elements of length n , ranging from 1 to n. All elements may not be present in the array. If the element is not present then there will be -1 present in the array. Rearrange the array such that A[i]=i and if i is not present display -1 at that place. Input format : The first line contains a n numbers with each number separated by space. Output format : Print the elements of the list after modification. Sample input : -1 -1 6 1 9 3 2 -1 4 -1 Sample Output : -1 1 2 3 4 -1 6 -1 -1 9 Explanation : The modified list contains elements such that A[i]=i . Code : Output :   2.  Formula Write a program that calculates and prints the value according to the given formula , Q=square root of [(2*C*D)/H]. Following are the fixed values of C and H , C=50 ,H=30. D is the variable whose values should be input to your program in a comma separated sequence. Input format : A sequence of values for D with each value separated by comma. Output format : Print the sequence of
Read more

ginortS in Python - HackerRank solution

-
Solution for hackerRank problem ginortS in Python Problem : You are given a string S.  S contains alphanumeric characters only.  'SORTING' Your task is to sort the string S in the following manner: All sorted lowercase letters are ahead of uppercase letters. All sorted uppercase letters are ahead of digits. All sorted odd digits are ahead of sorted even digits. Input Format A single line of input contains the string S. Constraints 0 < len(S) < 1000 Output Format Output the sorted string S. Sample Input Sorting1234 Sample Output ginortS1324 Code : s = str(input()) Upper = [] lower = [] odd_no = [] even_no = [] for i in s:     if(i.isupper()):         Upper += [i]     if(i.islower()):         lower += [i]     if(i.isnumeric()):         if(int(i)%2 == 0):             even_no += [i]         else :             odd_no += [i] Upper.sort() lower.sort() odd_no.sort() even_no.sort() Upper = "".join(Upper) lower = "".join(lower) odd = "".join(odd_no) ev
Read more