Find a string in python - HackerRank solution

Solution for hackerRank problem Find a string in python

Problem :

In this challenge, the user enters a string and a substring. You have to print the number of times that the substring occurs in the given string. String traversal will take place from left to right, not from right to left.

NOTE: String letters are case-sensitive.

Input Format

The first line of input contains the original string. The next line contains the substring.

Constraints

1 <= len(string) <= 200

Each character in the string is an ascii character.

Output Format

Output the integer number indicating the total number of occurrences of the substring in the original string.

Sample Input

ABCDCDC

CDC

Sample Output

2

Concept

Some string processing examples, such as these, might be useful.

There are a couple of new concepts:

In Python, the length of a string is found by the function len(s), where  is the string.

To traverse through the length of a string, use a for loop:

for i in range(0, len(s)):

    print (s[i])

A range function is used to loop over some length:

range (0, 5)

Here, the range loops over  to .  is excluded.

Procedure

1. Start.

2. Store the first letter of the sub string in a variable.

3. Initialize count as 0.

4. Loop from 0 to len(string)

=> if s[i] = first letter of sub string

    => loop from 0 to length of the sub string

        => check if each character of the string is equal to the corresponding character in the sub string

        => if all characters are equal then increment the count variable.

5. Print the count.

6. End.

Code :

def count_substring(string, sub_string):

    first = sub_string[0]

    count=0

    for i in range(len(string)):

        if(string[i]==first):

            flag=0

            for x in range(len(sub_string)):

                if((i+x)<len(string)):

                    if(string[i+x]==sub_string[x]):

                        continue

                    else :

                        flag = 1

                        break

                else :

                    flag=1

                        

            if(flag==0):

                count+=1

    return count

if __name__ == '__main__':

    string = input().strip()

    sub_string = input().strip()

    count = count_substring(string, sub_string)

    print(count)